Date: April 13, 2017
Capacitor; Capacitor Voltage-current Relations; Inductors; Inductor
Voltage-current Relations
Activity 1:
Capacitors in a Circuit
In this
activity, we use our understanding of how capacitors work in a DC-circuit to
obtain the amount of energy at each capacitor.
In the
picture above, the circuit is in DC-circuit; therefore, we replace all the
capacitors with open circuits. Because of this, we can now find the current, I,
because the resistors are all in series. Then, we find the voltages parallel to
the capacitor because they will be the same. Now that we have the voltage at
each capacitor, we use the energy equation for capacitors to solve for W1 and
W2.
Lab 1: Capacitor
Voltage-current Relations
Pre-lab:
In the above picture, we did the pre-lab where we sketched
out the capacitor voltage-current relation. The top graph was for a sinusoidal
wave and the bottom graph was for a triangular wave.
We were given that the resistor was 100ohms and the
capacitor was 1microF. We also put down the voltage we were applying and the
frequency.
For the picture above, the frequency was 1k-Hz and was a
sinusoidal wave input.
The picture above was for 2k-Hz and was a sinusoidal wave
input.
This picture was for 100Hz and was for a triangular wave input.
When we compare these to the pre-lab sketches we did, we
confirm that our prediction was correct.
Activity 2: Capacitor
Equivalence
This activity serves to remind us that the equivalent
capacitor can be determined just like the equivalent resistor.
The above picture shows step by step how each equivalent
capacitor is calculated. In series, they add together; in parallel, they follow
Req=(R1+R2)/(R1*R2).
Activity 3: Inductors
This activity serves as practice for using the inductors to
find current.
This is the picture of the question.
This is the step by step of solving for the current when an
inductor is in the circuit. First, we note that the voltage across an inductor
is a time dependent event. Then we write down the relationship between voltage,
inductors, and current. We solve for di then integrate to get current. We plug
in all the values to get the current at the specific time, i(t). Then we
realized that they gave us the initial current; therefore, we add them together
to get the final current.
Lab 2: Inductor
Voltage-current Relation
In this lab, our aim was to analyze the relation between the
voltage difference across an inductor and the current passing through it.
In the picture above, we applied a sinusoidal input voltage
at 1k-Hz, amplitude of 2V, and was offset to 0V.
In the picture above, we applied a sinusoidal input voltage
at 2k-Hz, amplitude 0f 2V, and was offset to 0V.
In Conclusion:
Today, we
learned about capacitor, inductors, and their relation of the voltage and
current running through them. In the first lab, we see that regardless of the
type of voltage wave we insert to the capacitor, the current wave will be the
derivative of that voltage wave. The second lab showed us that changing the
frequency results in a change in amplitude for the current.
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